这篇文章主要介绍“PostgreSQL中怎么在pg_locks和pg_stat_activity两张基表基础上创建的视图”，在日常操作中，相信很多人在PostgreSQL中怎么在pg_locks和pg_stat_activity两张基表基础上创建的视图问题上存在疑惑，小编查阅了各式资料，整理出简单好用的操作方法，希望对大家解答”PostgreSQL中怎么在pg_locks和pg_stat_activity两张基表基础上创建的视图”的疑惑有所帮助！接下来，请跟着小编一起来学习吧！

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显示阻塞信息的视图:

CREATE OR REPLACE VIEW vw_lockinfo
AS
SELECT blocked_locks.pid     AS blocked_pid,
         blocked_activity.usename  AS blocked_user,
         blocking_locks.pid     AS blocking_pid,
         blocking_activity.usename AS blocking_user,
         blocked_activity.query    AS blocked_statement,
         blocking_activity.query   AS current_statement_in_blocking_process
   FROM  pg_catalog.pg_locks         blocked_locks
    JOIN pg_catalog.pg_stat_activity blocked_activity  ON blocked_activity.pid = blocked_locks.pid
    JOIN pg_catalog.pg_locks         blocking_locks 
        ON blocking_locks.locktype = blocked_locks.locktype
        AND blocking_locks.DATABASE IS NOT DISTINCT FROM blocked_locks.DATABASE
        AND blocking_locks.relation IS NOT DISTINCT FROM blocked_locks.relation
        AND blocking_locks.page IS NOT DISTINCT FROM blocked_locks.page
        AND blocking_locks.tuple IS NOT DISTINCT FROM blocked_locks.tuple
        AND blocking_locks.virtualxid IS NOT DISTINCT FROM blocked_locks.virtualxid
        AND blocking_locks.transactionid IS NOT DISTINCT FROM blocked_locks.transactionid
        AND blocking_locks.classid IS NOT DISTINCT FROM blocked_locks.classid
        AND blocking_locks.objid IS NOT DISTINCT FROM blocked_locks.objid
        AND blocking_locks.objsubid IS NOT DISTINCT FROM blocked_locks.objsubid
        AND blocking_locks.pid != blocked_locks.pid
    JOIN pg_catalog.pg_stat_activity blocking_activity ON blocking_activity.pid = blocking_locks.pid
   WHERE NOT blocked_locks.GRANTED;
[local]:5432 pg12@testdb=# CREATE OR REPLACE VIEW vw_lockinfo
pg12@testdb-# AS
pg12@testdb-# SELECT blocked_locks.pid     AS blocked_pid,
pg12@testdb-#          blocked_activity.usename  AS blocked_user,
pg12@testdb-#          blocking_locks.pid     AS blocking_pid,
pg12@testdb-#          blocking_activity.usename AS blocking_user,
pg12@testdb-#          blocked_activity.query    AS blocked_statement,
pg12@testdb-#          blocking_activity.query   AS current_statement_in_blocking_process
pg12@testdb-#    FROM  pg_catalog.pg_locks         blocked_locks
pg12@testdb-#     JOIN pg_catalog.pg_stat_activity blocked_activity  ON blocked_activity.pid = blocked_locks.pid
pg12@testdb-#     JOIN pg_catalog.pg_locks         blocking_locks 
pg12@testdb-#         ON blocking_locks.locktype = blocked_locks.locktype
pg12@testdb-#         AND blocking_locks.DATABASE IS NOT DISTINCT FROM blocked_locks.DATABASE
pg12@testdb-#         AND blocking_locks.relation IS NOT DISTINCT FROM blocked_locks.relation
pg12@testdb-#         AND blocking_locks.page IS NOT DISTINCT FROM blocked_locks.page
pg12@testdb-#         AND blocking_locks.tuple IS NOT DISTINCT FROM blocked_locks.tuple
pg12@testdb-#         AND blocking_locks.virtualxid IS NOT DISTINCT FROM blocked_locks.virtualxid
pg12@testdb-#         AND blocking_locks.transactionid IS NOT DISTINCT FROM blocked_locks.transactionid
pg12@testdb-#         AND blocking_locks.classid IS NOT DISTINCT FROM blocked_locks.classid
pg12@testdb-#         AND blocking_locks.objid IS NOT DISTINCT FROM blocked_locks.objid
pg12@testdb-#         AND blocking_locks.objsubid IS NOT DISTINCT FROM blocked_locks.objsubid
pg12@testdb-#         AND blocking_locks.pid != blocked_locks.pid
pg12@testdb-#  
pg12@testdb-#     JOIN pg_catalog.pg_stat_activity blocking_activity ON blocking_activity.pid = blocking_locks.pid
pg12@testdb-#    WHERE NOT blocked_locks.GRANTED;
CREATE VIEW
Time: 131.424 ms
[local]:5432 pg12@testdb=# select * from vw_lockinfo;
-[ RECORD 1 ]-------------------------+---------------------------------------------------------------------------------------------------------------------------------------------------------------------
blocked_pid                           | 2184
blocked_user                          | pg12
blocking_pid                          | 2863
blocking_user                         | pg12
blocked_statement                     | update t_lock set id = 1000 where id = 1;
current_statement_in_blocking_process | select pid,locktype,relation::regclass,mode,page,tuple,virtualxid,transactionid,virtualtransaction,granted,fastpath from pg_locks where relation='t_lock'::regclass;
Time: 21.032 ms

显示带有时间属性的locks

CREATE OR REPLACE VIEW vw_lockinfo_time
AS
SELECT a.datname,
         l.relation::regclass,
         l.transactionid,
         l.mode,
         l.GRANTED,
         a.usename,
         a.query,
         a.query_start,
         age(now(), a.query_start) AS "age",
         a.pid
FROM pg_stat_activity a
JOIN pg_locks l ON l.pid = a.pid
ORDER BY a.query_start;
[local]:5432 pg12@testdb=# CREATE OR REPLACE VIEW vw_lockinfo_time
pg12@testdb-# AS
pg12@testdb-# SELECT a.datname,
pg12@testdb-#          l.relation::regclass,
pg12@testdb-#          l.transactionid,
pg12@testdb-#          l.mode,
pg12@testdb-#          l.GRANTED,
pg12@testdb-#          a.usename,
pg12@testdb-#          a.query,
pg12@testdb-#          a.query_start,
pg12@testdb-#          age(now(), a.query_start) AS "age",
pg12@testdb-#          a.pid
pg12@testdb-# FROM pg_stat_activity a
pg12@testdb-# JOIN pg_locks l ON l.pid = a.pid
pg12@testdb-# ORDER BY a.query_start;
CREATE VIEW
Time: 17.799 ms
[local]:5432 pg12@testdb=# select * from vw_lockinfo_time;
-[ RECORD 1 ]-+--------------------------------------------------------------------------------
-------------------------------------------------------------------------------------
datname       | testdb
relation      | t_lock
transactionid | 
mode          | RowExclusiveLock
granted       | t
usename       | pg12
query         | select pid,locktype,relation::regclass,mode,page,tuple,virtualxid,transactionid
,virtualtransaction,granted,fastpath from pg_locks where relation='t_lock'::regclass;
query_start   | 2019-08-13 15:32:23.139886+08
age           | 00:11:29.095421
pid           | 2863
...

到此，关于“PostgreSQL中怎么在pg_locks和pg_stat_activity两张基表基础上创建的视图”的学习就结束了，希望能够解决大家的疑惑。理论与实践的搭配能更好的帮助大家学习，快去试试吧！若想继续学习更多相关知识，请继续关注创新互联网站，小编会继续努力为大家带来更多实用的文章！

文章题目：PostgreSQL中怎么在pg_locks和pg_stat_activity两张基表基础上创建的视图
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