private static Boolean isQuit = false; 

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Timer timer = new Timer(); 

@Override

public boolean onKeyDown(int keyCode, KeyEvent event) { 

        if (keyCode == KeyEvent.KEYCODE_BACK) { 

            if (isQuit == false) { 

                isQuit = true; 

                Toast.makeText(getBaseContext(), "再按一次返回键退出程序", Toast.LENGTH_SHORT).show(); 

                TimerTask task = null; 

                task = new TimerTask() { 

                    @Override

                    public void run() { 

                        isQuit = false; 

                    } 

                }; 

                timer.schedule(task, 2000); 

            } else { 

                finish(); 

                System.exit(0); 

            } 

        } 

        return false; 

}

标题名称：android连续点击两次返回退出程序
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