关于Java走迷宫的问题。我已经有相关代码了，但是我看不懂。麻烦高手帮忙注释一下，然后再修改点儿。

package 走迷宫;

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import java.awt.BorderLayout;

import java.awt.Color;

import java.awt.GridLayout;

import java.awt.event.ActionEvent;

import java.awt.event.ActionListener;

import java.util.ArrayList;

import java.util.LinkedList;

import java.util.List;

import java.util.TimerTask;

import javax.swing.JButton;

import javax.swing.JFrame;

import javax.swing.JOptionPane;

import javax.swing.JPanel;

// 迷宫

public class Maze extends JFrame implements ActionListener {

private JPanel panel;

private JPanel northPanel;

private JPanel centerPanel;

private MazeGrid grid[][];

private JButton restart;

private JButton dostart;

private int rows;// rows 和cols目前暂定只能是奇数

private int cols;

private ListString willVisit;

private ListString visited;

private LinkedListString comed;

private long startTime;

private long endTime;

public Maze() {

rows = 25;

cols = 25;

willVisit = new ArrayListString();

visited = new ArrayListString();

comed = new LinkedListString();

init();

this.setTitle("回溯法--走迷宫");

this.add(panel);

this.pack();

this.setVisible(true);

this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

}

public void init() {

panel = new JPanel();

northPanel = new JPanel();

centerPanel = new JPanel();

panel.setLayout(new BorderLayout());

restart = new JButton("重新生成迷宫");

dostart = new JButton("开始走迷宫");

grid = new MazeGrid[rows][cols];

centerPanel.setLayout(new GridLayout(rows, cols, 1, 1));

centerPanel.setBackground(new Color(0, 0, 0));

northPanel.add(restart);

northPanel.add(dostart);

dostart.addActionListener(this);

restart.addActionListener(this);

for (int i = 0; i grid.length; i++)

for (int j = 0; j grid[i].length; j++) {

if (j % 2 == 0 i % 2 == 0)

grid[i][j] = new MazeGrid(true, 20, 20);

else

grid[i][j] = new MazeGrid(false, 20, 20);

}

grid[0][0].setVisited(true);

grid[0][0].setPersonCome(true);

grid[0][0].setStart(true);

visited.add("0#0");

grid[rows - 1][cols - 1].setEnd(true);

grid = createMap(grid, 0, 0);

for (int i = 0; i grid.length; i++)

for (int j = 0; j grid[i].length; j++) {

grid[i][j].repaint();

centerPanel.add(grid[i][j]);

}

panel.add(northPanel, BorderLayout.NORTH);

panel.add(centerPanel, BorderLayout.CENTER);

}

/**

* 生成迷宫

*

* @param mazeGrid

* @param x

* @param y

* @return

*/

public MazeGrid[][] createMap(MazeGrid mazeGrid[][], int x, int y) {

int visitX = 0;

int visitY = 0;

if (x - 2 = 0) {

if (!mazeGrid[x - 2][y].isVisited()) {

willVisit.add((x - 2) + "#" + y);

}

}

if (x + 2 cols) {

if (!mazeGrid[x + 2][y].isVisited()) {

willVisit.add((x + 2) + "#" + y);

}

}

if (y - 2 = 0) {

if (!mazeGrid[x][y - 2].isVisited()) {

willVisit.add(x + "#" + (y - 2));

}

}

if (y + 2 rows) {

if (!mazeGrid[x][y + 2].isVisited()) {

willVisit.add(x + "#" + (y + 2));

}

}

if (!willVisit.isEmpty()) {

int visit = (int) (Math.random() * willVisit.size());

String id = willVisit.get(visit);

visitX = Integer.parseInt(id.split("#")[0]);

visitY = Integer.parseInt(id.split("#")[1]);

mazeGrid[(visitX + x) / 2][(visitY + y) / 2].setMark(true);

mazeGrid[visitX][visitY].setVisited(true);

if (!visited.contains(id)) {// 将这个点加到已访问中去

visited.add(id);

}

willVisit.clear();

createMap(mazeGrid, visitX, visitY);

} else {

if (!visited.isEmpty()) {

String id = visited.remove(visited.size() - 1);// 取出最后一个元素

visitX = Integer.parseInt(id.split("#")[0]);

visitY = Integer.parseInt(id.split("#")[1]);

mazeGrid[visitX][visitY].setVisited(true);

createMap(mazeGrid, visitX, visitY);

}

}

return mazeGrid;

}

/**

* 走迷宫

*

* @param mazeGrid

* @param x

* @param y

*/

public String goMaze(MazeGrid mazeGrid[][], int x, int y) {

int comeX = 0;

int comeY = 0;

// left

if (x - 1 = 0) {

if (mazeGrid[x - 1][y].isMark()) {

if (!comed.contains((x - 1) + "#" + y))

willVisit.add((x - 1) + "#" + y);

}

}

// right

if (x + 1 cols) {

if (mazeGrid[x + 1][y].isMark()) {

if (!comed.contains((x + 1) + "#" + y))

willVisit.add((x + 1) + "#" + y);

}

}

// up

if (y - 1 = 0) {

if (mazeGrid[x][y - 1].isMark()) {

if (!comed.contains(x + "#" + (y - 1)))

willVisit.add(x + "#" + (y - 1));

}

}

// down

if (y + 1 rows) {

if (mazeGrid[x][y + 1].isMark()) {

if (!comed.contains(x + "#" + (y + 1)))

willVisit.add(x + "#" + (y + 1));

}

}

if (!willVisit.isEmpty()) {

int visit = (int) (Math.random() * willVisit.size());

String id = willVisit.get(visit);

comeX = Integer.parseInt(id.split("#")[0]);

comeY = Integer.parseInt(id.split("#")[1]);

mazeGrid[x][y].setPersonCome(false);

mazeGrid[comeX][comeY].setPersonCome(true);

mazeGrid[x][y].repaint();

mazeGrid[comeX][comeY].repaint();

willVisit.clear();

comed.add(x + "#" + y);

} else {

if (!comed.isEmpty()) {

String id = comed.removeLast();

comeX = Integer.parseInt(id.split("#")[0]);

comeY = Integer.parseInt(id.split("#")[1]);

mazeGrid[x][y].setPersonCome(false);

mazeGrid[comeX][comeY].setPersonCome(true);

mazeGrid[x][y].repaint();

mazeGrid[comeX][comeY].repaint();

comed.addFirst(x + "#" + y);

}

}

return comeX + "#" + comeY;

}

int comeX = 0;

int comeY = 0;

public void actionPerformed(ActionEvent e) {

if (e.getActionCommand().equals("重新生成迷宫")) {

refreshMap(grid);

} else if (e.getActionCommand().equals("开始走迷宫")) {

startTime = System.currentTimeMillis();

dostart.setVisible(false);

restart.setText("禁止刷新");

int delay = 1000;

int period = 500;// 循环间隔

java.util.Timer timer = new java.util.Timer();

timer.scheduleAtFixedRate(new TimerTask() {

public void run() {

if (grid[rows - 1][cols - 1].isPersonCome()) {

endTime = System.currentTimeMillis();

JOptionPane.showMessageDialog(null, "已经走出迷宫，耗时"

+ (endTime - startTime) / 1000 + "秒", "消息提示",

JOptionPane.ERROR_MESSAGE);

this.cancel();

restart.setText("重新生成迷宫");

} else {

String id = goMaze(grid, comeX, comeY);

comeX = Integer.parseInt(id.split("#")[0]);

comeY = Integer.parseInt(id.split("#")[1]);

}

}

}, delay, period);

}

}

/**

* 刷新地图

*/

public void refreshMap(MazeGrid mazeGrid[][]) {

comeX = 0;

comeY = 0;

willVisit.clear();

visited.clear();

comed.clear();

this.remove(panel);

init();

this.add(panel);

this.pack();

this.setVisible(true);

}

public static void main(String args[]) {

long start = System.currentTimeMillis();

new Maze();

long end = System.currentTimeMillis();

System.out.println("使用ArrayList生成迷宫耗时：" + (end - start) + "毫秒");

}

}

请帮忙用数据结构（java版）的知识解决这道迷宫问题的程序代码。

我这是用c写的。你可以看看，希望能帮助到你。

#include"stdlib.h"

#include"stdio.h"

#define N 50

#define M 50

int X;

int maze[N+2][M+2];

struct point{

int row,col,predecessor;

}queue[512];

int head=0,tail=0;

void shoudong_maze(int m,int n){

int i,j;

printf("\n\n");

printf("请按行输入迷宫，0表示通路，1表示障碍:\n\n");

for(i=0;im;i++)

for(j=0;jn;j++)

scanf("%d",maze[i][j]);

}

void zidong_maze(int m,int n){

int i,j;

printf("\n迷宫生成中……\n\n");

system("pause");

for(i=0;im;i++)

for(j=0;jn;j++)

maze[i][j]=rand()%2;

//由于rand()产生的随机数是从0到RAND_MAX

//RAND_MAX是定义在stdlib.h中的,其值至少为32767)

//要产生从X到Y的数,只需要这样写：k=rand()%(Y-X+1)+X;

}

void print_maze(int m,int n){

int i,j;

printf("\n迷宫生成结果如下:\n\n");

printf("迷宫入口\n");

printf("↓");

for(i=0;im;i++)

{printf("\n");

for(j=0;jn;j++)

{if(maze[i][j]==0) printf("□");

if(maze[i][j]==1) printf("■");}

}

printf("→迷宫出口\n");

}

void result_maze(int m,int n)

{ int i,j;

printf("迷宫通路(用☆表示)如下所示：\n\t");

for(i=0;im;i++)

{ printf("\n");

for(j=0;jn;j++)

{if(maze[i][j]==0||maze[i][j]==2) printf("□");

if(maze[i][j]==1) printf("■");

if(maze[i][j]==3) printf("☆");

}

}

}

void enqueue(struct point p)

{ queue[tail]=p;

tail++;

}

struct point dequeue()

{ head++;

return queue[head-1];

}

int is_empty()

{ return head==tail;

}

void visit(int row,int col,int maze[52][52])

{ struct point visit_point={row,col,head-1};

maze[row][col]=2;

enqueue(visit_point);

}

int mgpath(int maze[52][52],int m,int n)

{ X=1;

struct point p={0,0,-1};

if(maze[p.row][p.col]==1)

{ printf("\n===============================================\n");

printf("此迷宫无解\n\n");X=0;return 0;}

maze[p.row][p.col]=2;

enqueue(p);

while(!is_empty())

{p=dequeue();

if((p.row==m-1)(p.col==n-1)) break;

if((p.col+1n)(maze[p.row][p.col+1]==0)) visit(p.row,p.col+1,maze);

if((p.row+1m)(maze[p.row+1][p.col]==0)) visit(p.row+1,p.col,maze);

if((p.col-1=0)(maze[p.row][p.col-1]==0)) visit(p.row,p.col-1,maze);

if((p.row-1=0)(maze[p.row-1][p.col]==0)) visit(p.row-1,p.col,maze);

}

if(p.row==m-1p.col==n-1)

{printf("\n==================================================================\n");

printf("迷宫路径为：\n");

printf("(%d,%d)\n",p.row,p.col);

maze[p.row][p.col]=3;

while(p.predecessor!=-1)

{p=queue[p.predecessor];

printf("(%d,%d)\n",p.row,p.col);

maze[p.row][p.col]=3;

}

}

else {printf("\n=============================================================\n");

printf("此迷宫无解！\n\n");X=0;}

return 0;

}

int main()

{int i,m,n,cycle=0;

while(cycle!=(-1))

{

printf("********************************************************************************\n");

printf(" ☆欢迎进入迷宫求解系统☆\n");

printf(" 设计者:尹旭 林静波（信息2班）\n");

printf("********************************************************************************\n");

printf(" 手动生成迷宫 请按：1\n");

printf(" 自动生成迷宫 请按：2\n");

printf(" 退出 请按：3\n\n");

printf("********************************************************************************\n");

printf("\n");

printf("请选择你的操作：\n");

scanf("%d",i);

switch(i)

{case 1:printf("\n请输入行数：");

scanf("%d",m);

printf("\n");

printf("请输入列数：");

scanf("%d",n);

while((m=0||m50)||(n=0||n50))

{ printf("\n抱歉，你输入的行列数超出预设范围(0-50,0-50),请重新输入：\n\n");

printf("请输入行数：");

scanf("%d",m);

printf("\n");

printf("请输入列数：");

scanf("%d",n);

}

shoudong_maze(m,n);

print_maze(m,n);

mgpath(maze,m,n);

if(X!=0)

result_maze(m,n);

printf("\n\nPress Enter Contiue!\n");

getchar();

while(getchar()!='\n');

break;

case 2:printf("\n请输入行数：");

scanf("%d",m);

printf("\n");

printf("请输入列数：");

scanf("%d",n);

while((m=0||m50)||(n=0||n50))

{printf("\n抱歉，你输入的行列数超出预设范围(0-50,0-50),请重新输入：\n\n");

printf("请输入行数：");

scanf("%d",m);

printf("\n");

printf("请输入列数：");

scanf("%d",n);

}

zidong_maze(m,n);

print_maze(m,n);

mgpath(maze,m,n);

if(X!=0)

result_maze(m,n);

printf("\n\nPress Enter Contiue!\n");getchar();while(getchar()!='\n');break;

case 3:cycle=(-1);

break;

default:printf("\n");

printf("你的输入有误!\n");

printf("\nPress Enter Contiue!\n");

getchar();

while(getchar()!='\n');break;

}

}

}

JAVA迷宫问题，怎么输出所走路径的坐标

在Way函数的if(Maza[Loci][Locj]==0) 语句里面Maza[Loci][Locj]=2;前面加一句

System.out.println("The Maza route is ("+Loci+","+Locj+")");就打印出程序所走路径的坐标了.

求大佬讲解一下这段java代码

//直译了哦,只有片面的代码,只能靠推测,其他你自己补充下:

//这个主要是对一个图像控件设置了键盘侦听事件,按下键盘时候对其进行坐标移位操作

//必须知道:ImageView图像控件,显示图片或者其他;num是一个二位数组,这里可以理解成矩阵地图;

public void control(int[][] num, ImageView iv) {

//对控件设置键盘侦听,

iv.setOnKeyPressed(e - {

//设置一个变量,从下面使用看,这个应该是一个图像步进单位

int m = 30;

//以下为:try catch封装的键盘四向按键判断

try {

//字面意义推测:row应该是行,col应该是列,这是用二维数组画了一个矩阵地图,0不能走,1可以走;

//如果键盘按下的键是s,并且"行+1"小于地图中的行的个数,并且:地图[row+1行][col列]的值不等于0

if (e.getCode() == KeyCode.S  row + 1  num.length  num[row + 1][col] != 0) {

//就设置图像y坐标(在原有坐标的基础上进行一个步进单位的叠加)

iv.setY(iv.getY() + m);

//行递增1:row=row+1;

row++;

}

//其实这里与下面与上面都是一个道理,仅仅判断的条件与按键不同罢了

if (e.getCode() == KeyCode.W  row - 1 = 0  num[row - 1][col] != 0) {

iv.setY(iv.getY() - m);

   //行递减1

row--;

  }

//同上

if (e.getCode() == KeyCode.A  col - 1 = 0  num[row][col - 1] != 0) {

iv.setX(iv.getX() - m);

//列递减1

col--;

}

//同上

if (e.getCode() == KeyCode.D  col + 1  num[0].length  num[row][col + 1] != 0) {

iv.setX(iv.getX() + m);

//列递增1

col++;

  }

}catch (Exception n) {}

//如果行等于地图"行"的最大的索引值,并且列等于第一行数组的最大索引值

if (row == num.length - 1  col == num[0].length - 1) {

//就调用win函数;

win();

}

});

}

急！！求用Java实现牛郎织女迷宫问题的代码

不是不想帮你。像这种问题 需要去专业性网站去问。并且 分数一定要高。

比如 这个论坛里 高手都往这里走。 再高高的高手只会在自己的领域。不会上网上论坛。嘿嘿

求走迷宫问题的算法，要求用Java写的？

public class Maze { private int[][] maze = null;

private int[] xx = { 1, 0, -1, 0 };

private int[] yy = { 0, 1, 0, -1 };

private Queue queue = null; public Maze(int[][] maze) {

this.maze = maze;

queue = new Queue(maze.length * maze.length);

} public void go() {

Point outPt = new Point(maze.length - 1, maze[0].length - 1);

Point curPt = new Point(0, 0);

Node curNode = new Node(curPt, null);

maze[curPt.x][curPt.y] = 2;

queue.entryQ(curNode); while (!queue.isEmpty()) {

curNode = queue.outQ();

for (int i = 0; i xx.length; ++i) {

Point nextPt = new Point();

nextPt.x = (curNode.point).x + xx[i];

nextPt.y = (curNode.point).y + yy[i];

if (check(nextPt)) {

Node nextNode = new Node(nextPt, curNode);

queue.entryQ(nextNode);

maze[nextPt.x][nextPt.y] = 2;

if (nextPt.equals(outPt)) {

java.util.StackNode stack = new java.util.StackNode();

stack.push(nextNode);

while ((curNode = nextNode.previous) != null) {

nextNode = curNode;

stack.push(curNode);

}

System.out.println("A Path is:");

while (!stack.isEmpty()) {

curNode = stack.pop();

System.out.println(curNode.point);

}

return;

}

}

}

}

System.out.println("Non solution!");

} private boolean check(Point p) {

if (p.x 0 || p.x = maze.length || p.y 0 || p.y = maze[0].length) {

return false;

}

if (maze[p.x][p.y] != 0) {

return false;

}

return true;

} public static void main(String[] args) {

int[][] maze = {

{ 0, 0, 1, 0, 1, 0, 1, 0, 1, 0 },

{ 0, 0, 1, 1, 1, 0, 0, 0, 1, 0 },

{ 0, 1, 0, 0, 1, 0, 0, 0, 0, 1 },

{ 0, 0, 0, 0, 1, 0, 0, 0, 1, 1 },

{ 0, 0, 1, 0, 0, 0, 0, 0, 0, 1 },

{ 1, 0, 1, 0, 1, 0, 0, 1, 0, 0 },

{ 0, 1, 0, 0, 1, 0, 0, 1, 0, 1 },

{ 1, 0, 1, 0, 1, 1, 0, 1, 0, 0 }

};

new Maze(maze).go();

} private class Queue { Node[] array = null;

int size = 0;

int len = 0;

int head = 0;

int tail = 0; public Queue(int n) {

array = new Node[n + 1];

size = n + 1;

} public boolean entryQ(Node node) {

if (isFull()) {

return false;

}

tail = (tail + 1) % size;

array[tail] = node;

len++;

return true;

} public Node outQ() {

if (isEmpty()) {

return null;

}

head = (head + 1) % size;

len--;

return array[head];

} public boolean isEmpty() {

return (len == 0 || head == tail) ? true : false;

} public boolean isFull() {

return ((tail + 1) % size == head) ? true : false;

}

} private class Node { Point point = null;

Node previous = null; public Node() {

this(null,null);

} public Node(Point point, Node node) {

this.point = point;

this.previous = node;

}

} private class Point { int x = 0;

int y = 0; public Point() {

this(0, 0);

} public Point(int x, int y) {

this.x = x;

this.y = y;

} public boolean equals(Point p) {

return (x == p.x) (y == p.y);

} @Override

public String toString() {

return "(" + x + "," + y + ")";

}

}

}

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