LeetCode226:InvertBinaryTree二叉树反转
题目
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226. Invert Binary Tree
QuestionEditorial Solution
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Total Accepted: 109341
Total Submissions: 230799
Difficulty: Easy
Invert a binary tree.
4 / \ 2 7 / \ / \ 1 3 6 9
to
4 / \ 7 2 / \ / \ 9 6 3 1
Trivia:
This problem was inspired by this original tweet by Max Howell:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* invertTree(TreeNode* root) { TreeNode *p,*q; p = NULL; q = NULL; if(root != NULL) { p = root->left; q = root->right; root->left = q; root->right = p; invertTree(root->left); invertTree(root->right); } return root; } };
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