vb.net拟合多段线 多段线如何拟合
谁能提供一段vb在CAD中绘制多段线的实例代码作参考！
多线段没画过，
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线倒是画过，二话不说直接上代码你参考一下
绘制边框
Private Sub Command4_Click()
Set acadDoc = acadApp.ActiveDocument
link2
acadDoc.ActiveLayer = acadlay(0)
With adoRes
While Not .EOF
pt1(0) = !X: pt1(1) = !Y: pt1(2) = !z: pt2(0) = !X1: pt2(1) = !Y1: pt2(2) = !z1
draw pt1, pt2
.MoveNext
Wend
End With
pt1(0) = 0: pt1(1) = 0: pt1(2) = 0
pt2(0) = 20: pt2(1) = 10: pt2(2) = 0
draw pt1, pt2
'在坡
pt1(0) = 0: pt1(1) = 0: pt1(2) = 0
pt2(0) = 20: pt2(1) = 10: pt2(2) = 0
draw pt1, pt2
For c = 0 To 50 Step 10
pt1(0) = 0: pt1(1) = c: pt1(2) = 0
pt2(0) = 270: pt2(1) = c: pt2(2) = 0
draw pt1, pt2
Next c
pt1(0) = 20: pt1(1) = 0: pt1(2) = 0
pt2(0) = 20: pt2(1) = 190: pt2(2) = 0
draw pt1, pt2
pt1(0) = 0: pt1(1) = 0: pt1(2) = 0
pt2(0) = 0: pt2(1) = -10: pt2(2) = 0
draw pt1, pt2
pt1(0) = 0: pt1(1) = -10: pt1(2) = 0
pt2(0) = 270: pt2(1) = -10: pt2(2) = 0
draw pt1, pt2
pt1(0) = 270: pt1(1) = -10: pt1(2) = 0
pt2(0) = 270: pt2(1) = 0: pt2(2) = 0
draw pt1, pt2
pt3(0) = 5: pt3(1) = -7
acadDoc.ModelSpace.AddText t, pt3, 4
pt3(0) = 55: pt3(1) = -7
acadDoc.ModelSpace.AddText t1, pt3, 4
a = 0
For c = 60 To 100 Step 10
pt1(0) = 20: pt1(1) = c: pt1(2) = 0
pt2(0) = 23: pt2(1) = c: pt2(2) = 0
draw pt1, pt2
pt1(0) = 10: pt1(1) = c - 1.6: pt1(2) = 0
acadDoc.ModelSpace.AddText a, pt1, 3.2
a = a + 2
Next c
'在图中加入地面高程
acadDoc.ActiveTextStyle = acadDoc.TextStyles.Add("楷体")
pt1(0) = 1: pt1(1) = 13: pt1(2) = 0
Set acadtext = acadDoc.ModelSpace.AddText("地面高程", pt1, 3.2)
Call rote1(acadtext, pt1)
'在图中加入设计高程
Call rote1(acadtext, pt1)
pt1(0) = 1: pt1(1) = 23: pt1(2) = 0
Set acadtext = acadDoc.ModelSpace.AddText("设计高程", pt1, 3.2)
Call rote1(acadtext, pt1)
'在图中加入填挖高
pt1(0) = 1: pt1(1) = 33: pt1(2) = 0
Set acadtext = acadDoc.ModelSpace.AddText("填 挖 高", pt1, 3.2)
Call rote1(acadtext, pt1)
'在图中加入坡度/坡长
pt1(0) = 0: pt1(1) = 5.5: pt1(2) = 0
Set acadtext = acadDoc.ModelSpace.AddText("坡 度", pt1, 3.2)
Call rote1(acadtext, pt1)
pt1(0) = 9: pt1(1) = 1: pt1(2) = 0
Set acadtext = acadDoc.ModelSpace.AddText("坡 长", pt1, 3.2)
Call rote1(acadtext, pt1)
'在图中加入桩号
pt1(0) = 1: pt1(1) = 43: pt1(2) = 0
Set acadtext = acadDoc.ModelSpace.AddText("桩 号", pt1, 3.2)
Call rote1(acadtext, pt1)
Call Command5_Click
End Sub
Private Sub draw(pt1, pt2)
Set AcadLine = acadDoc.ModelSpace.AddLine(pt1, pt2)
acadDoc.Regen acActiveViewport
End Sub
线倒是画过，二话不说直接上代码你参考一下
vb曲线拟合
老弟，公式打不出来的
一般都是用matlab搞定的，它里面有现成的函数供使用的
典型程序解析：
x=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1];%input xi data
y=[1.978 3.28 6.16 7.08 7.34 7.66 9.56 9.48 9.30 11.2]; % input yi data
n=2; % polynomial order
p=polyfit(x, y, n)% polyfit 的输出是一个多项式系数的行向量（拟合二项式的系数）
ezplot('-9.8108*x*x+20.1293*x-0.0317')%对拟合的函数作图
xi=linspace(0,1,100); % x-axis data for plotting
z=polyval(p, xi);% 为了计算在xi数据点的多项式值，调用MATLAB的函数polyval
plot(x,y, 'o' ,x,y,xi,z,':')%在同一个图形里看他们的拟合程度
典型例题：对以下数据分别作二次,三次多项式拟合,并画出图形.
x=1:16;
y=[4, 6.4, 8, 8.4, 9.28, 9.5, 9.7, 9.86, 10, 10.2, 10.32, 10.42, 10.5, 10.55, 10.58, 10.6];
源程序：二次多项式拟合
x=1:1:16;
y=[4, 6.4, 8, 8.4, 9.28, 9.5, 9.7, 9.86, 10, 10.2, 10.32, 10.42, 10.5, 10.55, 10.58, 10.6];
a=polyfit(x,y,2)
a =
-0.0445 1.0711 4.3252
ezplot('-0.0445*x^2+1.0711*x+4.3252')
三次多项式拟合
x=1:1:16;
y=[4, 6.4, 8, 8.4, 9.28, 9.5, 9.7, 9.86, 10, 10.2, 10.32, 10.42, 10.5, 10.55, 10.58, 10.6];
a=polyfit(x,y,3)
a =
0.0060 -0.1963 2.1346 2.5952
ezplot('0.0060*x^3-0.1963*x^2+2.1346*x+2.5952')
VB.NET 简单多线程
多线程一般是不推荐用的，因为线程之间如果有共享资源的话会引起竞争，需要加锁处理；而且线程间没有时序关系，所以你在调试中可能会出现异步处理结束顺序与开始处理顺序不一致的情况（我在调试中已经发现该问题）。
针对你提出的这个问题，采用了多线程处理，利用的是BackgroundWorker也就是异步处理控件进行了处理。
代码已经经过调试通过。欢迎交流，如有问题，留下QQ或其他联系方式。
代码如下，并附程序截图。
‘---------------------------------------------------
Imports System.ComponentModel '导入异步控件命名空间
Public Class Form1
Private howmany As Integer = 10
Private AnalysisNumber(0 To howmany - 1) As BackgroundWorker
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
ListBox1.Items.Clear()
creatNewBackgroundWorker()
addHandle()
startWork()
End Sub
Private Sub creatNewBackgroundWorker()
For i As Integer = 0 To AnalysisNumber.Length - 1
AnalysisNumber(i) = New BackgroundWorker
Next
End Sub
Private Sub addHandle()
For i As Integer = 0 To AnalysisNumber.Length - 1
AddHandler AnalysisNumber(i).DoWork, AddressOf AnalysisNumber_DoWork
AddHandler AnalysisNumber(i).RunWorkerCompleted, AddressOf AnalysisNumber_RunWorkerCompleted
Next
End Sub
Private Sub startWork()
For i As Integer = 0 To 9
Dim temp(0 To 9) As Integer
For j As Integer = 1 To 10
temp(j - 1) = 10 * i + j
Next
AnalysisNumber(i).RunWorkerAsync(temp)
Next
End Sub
Private Sub AnalysisNumber_DoWork(ByVal sender As Object, ByVal e As System.ComponentModel.DoWorkEventArgs)
Dim data As Integer()
data = CType(e.Argument, Integer())
Dim temp As Integer
For i As Integer = 0 To data.Length - 1
temp = data(i)
data(i) = temp * temp
Next
e.Result = data
End Sub
Private Sub AnalysisNumber_RunWorkerCompleted(ByVal sender As Object, ByVal e As System.ComponentModel.RunWorkerCompletedEventArgs)
Dim data As Integer()
data = CType(e.Result, Integer())
For i As Integer = 0 To data.Length - 1
ListBox1.Items.Add(data(i))
Next
End Sub
End Class
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