用JAVA写二叉树

/**

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* [Tree2.java] Create on 2008-10-20 下午03:03:24

* Copyright (c) 2008 by iTrusChina.

*/

/**

* @author WangXuanmin

* @version 0.10

*/

public class Tree2Bef {

private StringBuffer bef=new StringBuffer();

//传入中序遍历和后序遍历,返回前序遍历字串

public String getBef(String mid, String beh) {

//若节点存在则向bef中添加该节点,继续查询该节点的左子树和右子树

if (root(mid, beh) != -1) {

int rootindex=root(mid, beh);

char root=mid.charAt(rootindex);

bef.append(root);

System.out.println(bef.toString());

String mleft, mright;

mleft = mid.substring(0,rootindex);

mright = mid.substring(rootindex+1);

getBef(mleft,beh);

getBef(mright,beh);

}

//所有节点查询完毕,返回前序遍历值

return bef.toString();

}

//从中序遍历中根据后序遍历查找节点索引值index

private int root(String mid, String beh) {

char[] midc = mid.toCharArray();

char[] behc = beh.toCharArray();

for (int i = behc.length-1; i -1; i--) {

for (int j = 0; j midc.length; j++) {

if (behc[i] == midc[j])

return j;

}

}

return -1;

}

public static void main(String[] args) {

Tree2Bef tree=new Tree2Bef();

String mid="84925163A7B";

String bef="894526AB731";

System.out.println(tree.getBef(mid,bef));

}

}

树结构如图:

1

|-------|

2 3

|---| |---|

4 5 6 7

|-| |-|

8 9 A B

用java怎么构造一个二叉树？

二叉树的相关操作，包括创建，中序、先序、后序（递归和非递归），其中重点的是java在先序创建二叉树和后序非递归遍历的的实现。

package com.algorithm.tree;

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Queue;

import java.util.Scanner;

import java.util.Stack;

import java.util.concurrent.LinkedBlockingQueue;

public class Tree {

private Node root;

public Tree() {

}

public Tree(Node root) {

this.root = root;

}

//创建二叉树

public void buildTree() {

Scanner scn = null;

try {

scn = new Scanner(new File("input.txt"));

} catch (FileNotFoundException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

root = createTree(root,scn);

}

//先序遍历创建二叉树

private Node createTree(Node node,Scanner scn) {

String temp = scn.next();

if (temp.trim().equals("#")) {

return null;

} else {

node = new Node((T)temp);

node.setLeft(createTree(node.getLeft(), scn));

node.setRight(createTree(node.getRight(), scn));

return node;

}

}

//中序遍历(递归)

public void inOrderTraverse() {

inOrderTraverse(root);

}

public void inOrderTraverse(Node node) {

if (node != null) {

inOrderTraverse(node.getLeft());

System.out.println(node.getValue());

inOrderTraverse(node.getRight());

}

}

//中序遍历(非递归)

public void nrInOrderTraverse() {

StackNode stack = new StackNode();

Node node = root;

while (node != null || !stack.isEmpty()) {

while (node != null) {

stack.push(node);

node = node.getLeft();

}

node = stack.pop();

System.out.println(node.getValue());

node = node.getRight();

}

}

//先序遍历(递归)

public void preOrderTraverse() {

preOrderTraverse(root);

}

public void preOrderTraverse(Node node) {

if (node != null) {

System.out.println(node.getValue());

preOrderTraverse(node.getLeft());

preOrderTraverse(node.getRight());

}

}

//先序遍历（非递归）

public void nrPreOrderTraverse() {

StackNode stack = new StackNode();

Node node = root;

while (node != null || !stack.isEmpty()) {

while (node != null) {

System.out.println(node.getValue());

stack.push(node);

node = node.getLeft();

}

node = stack.pop();

node = node.getRight();

}

}

//后序遍历(递归)

public void postOrderTraverse() {

postOrderTraverse(root);

}

public void postOrderTraverse(Node node) {

if (node != null) {

postOrderTraverse(node.getLeft());

postOrderTraverse(node.getRight());

System.out.println(node.getValue());

}

}

//后续遍历(非递归)

public void nrPostOrderTraverse() {

StackNode stack = new StackNode();

Node node = root;

Node preNode = null;//表示最近一次访问的节点

while (node != null || !stack.isEmpty()) {

while (node != null) {

stack.push(node);

node = node.getLeft();

}

node = stack.peek();

if (node.getRight() == null || node.getRight() == preNode) {

System.out.println(node.getValue());

node = stack.pop();

preNode = node;

node = null;

} else {

node = node.getRight();

}

}

}

//按层次遍历

public void levelTraverse() {

levelTraverse(root);

}

public void levelTraverse(Node node) {

QueueNode queue = new LinkedBlockingQueueNode();

queue.add(node);

while (!queue.isEmpty()) {

Node temp = queue.poll();

if (temp != null) {

System.out.println(temp.getValue());

queue.add(temp.getLeft());

queue.add(temp.getRight());

}

}

}

}

//树的节点

class Node {

private Node left;

private Node right;

private T value;

public Node() {

}

public Node(Node left,Node right,T value) {

this.left = left;

this.right = right;

this.value = value;

}

public Node(T value) {

this(null,null,value);

}

public Node getLeft() {

return left;

}

public void setLeft(Node left) {

this.left = left;

}

public Node getRight() {

return right;

}

public void setRight(Node right) {

this.right = right;

}

public T getValue() {

return value;

}

public void setValue(T value) {

this.value = value;

}

}

测试代码：

package com.algorithm.tree;

public class TreeTest {

/**

* @param args

*/

public static void main(String[] args) {

Tree tree = new Tree();

tree.buildTree();

System.out.println("中序遍历");

tree.inOrderTraverse();

tree.nrInOrderTraverse();

System.out.println("后续遍历");

//tree.nrPostOrderTraverse();

tree.postOrderTraverse();

tree.nrPostOrderTraverse();

System.out.println("先序遍历");

tree.preOrderTraverse();

tree.nrPreOrderTraverse();

//

}

}

java二叉树的顺序表实现

做了很多年的程序员，觉得什么树的设计并不是非常实用。二叉树有顺序存储，当一个insert大量同时顺序自增插入的时候，树就会失去平衡。树的一方为了不让塌陷，会增大树的高度。性能会非常不好。以上是题外话。分析需求在写代码。

import java.util.List;

import java.util.LinkedList;

public class Bintrees {

private int[] array = {1, 2, 3, 4, 5, 6, 7, 8, 9};

private static ListNode nodeList = null;

private static class Node {

Node leftChild;

Node rightChild;

int data;

Node(int newData) {

leftChild = null;

rightChild = null;

data = newData;

}

}

// 创建二叉树

public void createBintree() {

nodeList = new LinkedListNode();

// 将数组的值转换为node

for (int nodeIndex = 0; nodeIndex array.length; nodeIndex++) {

nodeList.add(new Node(array[nodeIndex]));

}

// 对除最后一个父节点按照父节点和孩子节点的数字关系建立二叉树

for (int parentIndex = 0; parentIndex array.length / 2 - 1; parentIndex++) {

nodeList.get(parentIndex).leftChild = nodeList.get(parentIndex * 2 + 1);

nodeList.get(parentIndex).rightChild = nodeList.get(parentIndex * 2 + 2);

}

// 最后一个父节点

int lastParentIndex = array.length / 2 - 1;

// 左孩子

nodeList.get(lastParentIndex).leftChild = nodeList.get(lastParentIndex * 2 + 1);

// 如果为奇数，建立右孩子

if (array.length % 2 == 1) {

nodeList.get(lastParentIndex).rightChild = nodeList.get(lastParentIndex * 2 + 2);

}

}

// 前序遍历

public static void preOrderTraverse(Node node) {

if (node == null) {

return;

}

System.out.print(node.data + " ");

preOrderTraverse(node.leftChild);

preOrderTraverse(node.rightChild);

}

// 中序遍历

public static void inOrderTraverse(Node node) {

if (node == null) {

return;

}

inOrderTraverse(node.leftChild);

System.out.print(node.data + " ");

inOrderTraverse(node.rightChild);

}

// 后序遍历

public static void postOrderTraverse(Node node) {

if (node == null) {

return;

}

postOrderTraverse(node.leftChild);

postOrderTraverse(node.rightChild);

System.out.print(node.data + " ");

}

public static void main(String[] args) {

Bintrees binTree = new Bintrees();

binTree.createBintree();

Node root = nodeList.get(0);

System.out.println("前序遍历：");

preOrderTraverse(root);

System.out.println();

System.out.println("中序遍历：");

inOrderTraverse(root);

System.out.println();

System.out.println("后序遍历：");

postOrderTraverse(root);

}

}

说明生活中遇到的二叉树，用java实现二叉树. (求源码，要求简练、易懂。非常满意会额外加分)

import java.util.ArrayList;

// 树的一个节点

class TreeNode {

Object _value = null; // 他的值

TreeNode _parent = null; // 他的父节点，根节点没有PARENT

ArrayList _childList = new ArrayList(); // 他的孩子节点

public TreeNode( Object value, TreeNode parent ){

this._parent = parent;

this._value = value;

}

public TreeNode getParent(){

return _parent;

}

public String toString() {

return _value.toString();

}

}

public class Tree {

// 给出宽度优先遍历的值数组，构建出一棵多叉树

// null 值表示一个层次的结束

// "|" 表示一个层次中一个父亲节点的孩子输入结束

// 如：给定下面的值数组：

// { "root", null, "left", "right", null }

// 则构建出一个根节点，带有两个孩子("left","right")的树

public Tree( Object[] values ){

// 创建根

_root = new TreeNode( values[0], null );

// 创建下面的子节点

TreeNode currentParent = _root; // 用于待创建节点的父亲

//TreeNode nextParent = null;

int currentChildIndex = 0; // 表示 currentParent 是他的父亲的第几个儿子

//TreeNode lastNode = null; // 最后一个创建出来的TreeNode，用于找到他的父亲

for ( int i = 2; i values.length; i++ ){

// 如果null ,表示下一个节点的父亲是当前节点的父亲的第一个孩子节点

if ( values[i] == null ){

currentParent = (TreeNode)currentParent._childList.get(0);

currentChildIndex = 0;

continue;

}

// 表示一个父节点的所有孩子输入完毕

if ( values[i].equals("|") ){

if ( currentChildIndex+1 currentParent._childList.size() ){

currentChildIndex++;

currentParent = (TreeNode)currentParent._parent._childList.get(currentChildIndex);

}

continue;

}

TreeNode child = createChildNode( currentParent, values[i] );

}

}

TreeNode _root = null;

public TreeNode getRoot(){

return _root;

}

/**

// 按宽度优先遍历，打印出parent子树所有的节点

private void printSteps( TreeNode parent, int currentDepth ){

for ( int i = 0; i parent._childList.size(); i++ ){

TreeNode child = (TreeNode)parent._childList.get(i);

System.out.println(currentDepth+":"+child);

}

if ( parent._childList.size() != 0 ) System.out.println(""+null);// 为了避免叶子节点也会打印null

//打印 parent 同层的节点的孩子

if ( parent._parent != null ){ // 不是root

int i = 1;

while ( i parent._parent._childList.size() ){// parent 的父亲还有孩子

TreeNode current = (TreeNode)parent._parent._childList.get(i);

printSteps( current, currentDepth );

i++;

}

}

// 递归调用，打印所有节点

for ( int i = 0; i parent._childList.size(); i++ ){

TreeNode child = (TreeNode)parent._childList.get(i);

printSteps( child, currentDepth+1 );

}

}

// 按宽度优先遍历，打印出parent子树所有的节点

public void printSteps(){

System.out.println(""+_root);

System.out.println(""+null);

printSteps(_root, 1 );

}**/

// 将给定的值做为 parent 的孩子，构建节点

private TreeNode createChildNode( TreeNode parent, Object value ){

TreeNode child = new TreeNode( value , parent );

parent._childList.add( child );

return child;

}

public static void main(String[] args) {

Tree tree = new Tree( new Object[]{ "root", null,

"left", "right", null,

"l1","l2","l3", "|", "r1","r2",null } );

//tree.printSteps();

System.out.println(""+ ( (TreeNode)tree.getRoot()._childList.get(0) )._childList.get(0) );

System.out.println(""+ ( (TreeNode)tree.getRoot()._childList.get(0) )._childList.get(1) );

System.out.println(""+ ( (TreeNode)tree.getRoot()._childList.get(0) )._childList.get(2) );

System.out.println(""+ ( (TreeNode)tree.getRoot()._childList.get(1) )._childList.get(0) );

System.out.println(""+ ( (TreeNode)tree.getRoot()._childList.get(1) )._childList.get(1) );

}

}

看一下吧！这是在网上找的一个例子！看对你有没有帮助！

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