vb点虐 crc效验 crc校验vb源代码

vb如何实现CRC12校验

Private Sub Form_Load()

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'text1为校验对象

Text1.Text = "31303432"

'text2为校验多项式

Text2.Text = "180D"

End Sub

Private Sub Command1_Click()

Text3.Text = CRC(Text1.Text, Text2.Text, 12)

End Sub

Private Function CRC(ByVal Hex_Number As String, ByVal Hex_CRC As String, Optional ByVal C As Integer = 16) As String

'Hex_Number为校验项16进制数字，Hex_CRC为校验多项式，16进制，C为默认位数CRC-16

Dim i As Integer

Dim BinNumber As String

Dim BinCRC As String

Dim Temp As String

CRC = "0"

If Hex_Number = "0" Then Exit Function

BinNumber = HEXtoBin(Hex_Number)

BinCRC = HEXtoBin(Hex_CRC)

i = Len(BinCRC)

BinNumber = BinNumber String(C, "0")

CRC = Left(BinNumber, i)

Temp = Right(BinNumber, Len(BinNumber) - i)

Temp = HEXtoBin(Hex(CLng("H" BINtoHEX(CRC)) Xor CLng("H" Hex_CRC))) Temp

CRC = BINtoHEX(Temp)

If Len(Temp) = i Then

CRC = CRC(CRC, Hex_CRC, 0)

End If

End Function

Private Function HEXtoBin(Hex_Number) As String

'十六进制转换为二进制

Dim i As Long

Dim B As String

Hex_Number = UCase(Hex_Number)

For i = 1 To Len(Hex_Number)

Select Case Mid(Hex_Number, i, 1)

Case "0": B = B "0000"

Case "1": B = B "0001"

Case "2": B = B "0010"

Case "3": B = B "0011"

Case "4": B = B "0100"

Case "5": B = B "0101"

Case "6": B = B "0110"

Case "7": B = B "0111"

Case "8": B = B "1000"

Case "9": B = B "1001"

Case "A": B = B "1010"

Case "B": B = B "1011"

Case "C": B = B "1100"

Case "D": B = B "1101"

Case "E": B = B "1110"

Case "F": B = B "1111"

End Select

Next i

While Left(B, 1) = "0"

B = Right(B, Len(B) - 1)

Wend

HEXtoBin = B

End Function

Private Function BINtoHEX(ByVal Bin_Number As String) As String

'二进制转换为十六进制

Dim i As Long

Dim H As String

If Len(Bin_Number) Mod 4 0 Then

Bin_Number = String(4 - Len(Bin_Number) Mod 4, "0") Bin_Number

End If

For i = 1 To Len(Bin_Number) Step 4

Select Case Mid(Bin_Number, i, 4)

Case "0000": H = H "0"

Case "0001": H = H "1"

Case "0010": H = H "2"

Case "0011": H = H "3"

Case "0100": H = H "4"

Case "0101": H = H "5"

Case "0110": H = H "6"

Case "0111": H = H "7"

Case "1000": H = H "8"

Case "1001": H = H "9"

Case "1010": H = H "A"

Case "1011": H = H "B"

Case "1100": H = H "C"

Case "1101": H = H "D"

Case "1110": H = H "E"

Case "1111": H = H "F"

End Select

Next i

While Left(H, 1) = "0"

H = Right(H, Len(H) - 1)

Wend

BINtoHEX = H

End Function

vb crc冗余校验

计算法就是依据CRC校验码的产生原理来设计程序。其优点是模块代码少，修改灵活，可移植性好。其缺点为计算量大。为了便于理解，这里假定了三位数据，而多项式码为A001(hex)。

在窗体上放置一命令按钮Command1，并添加如下代码：

Private Sub Command1_Click()

　Dim CRC() As Byte

　Dim d() As Byte '待传输数据

　ReDim d(2) As Byte

　d(0) = 123

　d(1) = 112

　d(2) = 135

　CRC = CRC16(d) '调用CRC16计算函数

　'CRC(0)为高位

　'CRC(1)为低位

End Sub

注意：在数据传输时CRC的低位可能在前，而高位在后。

如何在vb中写crc32校验

两种方法：

1、查表法通过字节内容查表后与下一个字节异或，再查表，再异或，直至最后得到校验码。在VB中设置定义数组后查表即可。

2、计算法按照crc多项式，自己编写子程序进行计算，输入变量为需要校验的字节（可定义成字节数组），返回校验码。

VB CRC校验问题

大概看了下。有变量定义类型错误，修改如下：

Public

Function

crc16(ByRef

cmdstring()

Byte,

DataLen

Integer)

String

Dim

data

Integer

Dim

Integer

Dim

CRCHi

long,

CRCLo

long'这里应该定义为long.因为下面赋值是long型。朋友。

Dim

iIndex

Long

Dim

CRCStr

String

Dim

DataStr

String

CRCLo

HFF'看这里的赋值。long型

CRCHi

HFF

For

DataLen

iIndex

CRCLo

Xor

cmdstring(i)

CRCLo

CRCHi

Xor

GetCRCLo(iIndex)

'低位处理

CRCHi

GetCRCHi(iIndex)

'高位处理

DataStr

Chr(cmdstring(i))

Dim

ReturnData(1)

Byte

ReturnData(1)

CRCHi

ReturnData(0)

CRCLo

CRCStr

StrConv(ReturnData,

vbUnicode)

crc16

DataStr

CRCStr

End

Function

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vb点虐 crc效验 crc校验vb源代码

vb如何实现CRC12校验

vb crc冗余校验

如何在vb中写crc32校验

VB CRC校验问题

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