c语言makeup函数 c语言mktime函数
C语言!和文件有关
#include "stdio.h"
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#include malloc.h
#include stdlib.h
struct Student
{
int num;
char name[20];
int score;
}student;
struct list
{
struct Student stu;
struct list *next;
};
struct list* creat(struct list *head,struct Student student)//建表
{
struct list *p1,*p2,*p;
p = head;
p1 = (struct list *)malloc(sizeof(struct list));
p1-stu = student;
if (head == NULL)
{
head = p1;
p1-next = NULL;
}
else
{
while (p-next != NULL)
{
p2 = p;
p = p-next;
}
if (head == p)
{
p-next = p1;
p1-next = NULL;
}
else
{
p2-next = p1;
p1-next = NULL;
}
}
return head;
}
void Print(struct list *head)//输出
{
FILE *fp;
fp = fopen("SCORE.DAT1","w");
if (fp == NULL)
{
printf("open file failed!\n");
exit(0);
}
struct list *p,*q;
p = head;
while (p != NULL)
{
fprintf(fp,"%d %s %d\n",p-stu.num,p-stu.name,p-stu.score);
q = p-next;
free(p);
p = q;
}
fclose(fp);
}
main()
{
struct list *head;
int makeup;
FILE *fp,*fpp;
head = NULL;
fp = fopen("SCORE.DAT","r");
fpp = fopen("BK.DAT","r");
if (fp == NULL)
{
printf("open file failed!\n");
exit(0);
}
if (fpp == NULL)
{
printf("open file failed!\n");
exit(0);
}
while (!feof(fp) !feof(fpp))//读取数据
{
fscanf(fp,"%d%s%*c%d",student.num,student.name,student.score);
fscanf(fpp,"%d",makeup);
if (makeup = 60)
{
student.score = 60;
}
else
{
if (makeup student.score)
{
student.score = makeup;
}
}
head = creat(head,student);
}
Print(head);
fclose(fp);
fclose(fpp);
}
求C语言函数大全
函数名: abort
功 能: 异常终止一个进程
用 法: void abort(void);
程序例:
#include stdio.h
#include stdlib.h
int main(void)
{
printf("Calling abort()\n");
abort();
return 0; /* This is never reached */
}
函数名: abs
功 能: 求整数的绝对值
用 法: int abs(int i);
程序例:
#include stdio.h
#include math.h
int main(void)
{
int number = -1234;
printf("number: %d absolute value: %d\n", number, abs(number));
return 0;
}
函数名: absread, abswirte
功 能: 绝对磁盘扇区读、写数据
用 法: int absread(int drive, int nsects, int sectno, void *buffer);
int abswrite(int drive, int nsects, in tsectno, void *buffer);
程序例:
/* absread example */
#include stdio.h
#include conio.h
#include process.h
#include dos.h
int main(void)
{
int i, strt, ch_out, sector;
char buf[512];
printf("Insert a diskette into drive A and press any key\n");
getch();
sector = 0;
if (absread(0, 1, sector, buf) != 0)
{
perror("Disk problem");
exit(1);
}
printf("Read OK\n");
strt = 3;
for (i=0; i80; i++)
{
ch_out = buf[strt+i];
putchar(ch_out);
}
printf("\n");
return(0);
}
函数名: access
功 能: 确定文件的访问权限
用 法: int access(const char *filename, int amode);
程序例:
#include stdio.h
#include io.h
int file_exists(char *filename);
int main(void)
{
printf("Does NOTEXIST.FIL exist: %s\n",
file_exists("NOTEXISTS.FIL") ? "YES" : "NO");
return 0;
}
int file_exists(char *filename)
{
return (access(filename, 0) == 0);
}
函数名: acos
功 能: 反余弦函数
用 法: double acos(double x);
程序例:
#include stdio.h
#include math.h
int main(void)
{
double result;
double x = 0.5;
result = acos(x);
printf("The arc cosine of %lf is %lf\n", x, result);
return 0;
}
函数名: allocmem
功 能: 分配DOS存储段
用 法: int allocmem(unsigned size, unsigned *seg);
程序例:
#include dos.h
#include alloc.h
#include stdio.h
int main(void)
{
unsigned int size, segp;
int stat;
size = 64; /* (64 x 16) = 1024 bytes */
stat = allocmem(size, segp);
if (stat == -1)
printf("Allocated memory at segment: %x\n", segp);
else
printf("Failed: maximum number of paragraphs available is %u\n",
stat);
return 0;
}
函数名: arc
功 能: 画一弧线
用 法: void far arc(int x, int y, int stangle, int endangle, int radius);
程序例:
#include graphics.h
#include stdlib.h
#include stdio.h
#include conio.h
int main(void)
{
/* request auto detection */
int gdriver = DETECT, gmode, errorcode;
int midx, midy;
int stangle = 45, endangle = 135;
int radius = 100;
/* initialize graphics and local variables */
initgraph(gdriver, gmode, "");
/* read result of initialization */
errorcode = graphresult(); /* an error occurred */
if (errorcode != grOk)
{
printf("Graphics error: %s\n", grapherrormsg(errorcode));
printf("Press any key to halt:");
getch();
exit(1); /* terminate with an error code */
}
midx = getmaxx() / 2;
midy = getmaxy() / 2;
setcolor(getmaxcolor());
/* draw arc */
arc(midx, midy, stangle, endangle, radius);
/* clean up */
getch();
closegraph();
return 0;
}
函数名: asctime
功 能: 转换日期和时间为ASCII码
用 法: char *asctime(const struct tm *tblock);
程序例:
#include stdio.h
#include string.h
#include time.h
int main(void)
{
struct tm t;
char str[80];
/* sample loading of tm structure */
t.tm_sec = 1; /* Seconds */
t.tm_min = 30; /* Minutes */
t.tm_hour = 9; /* Hour */
t.tm_mday = 22; /* Day of the Month */
t.tm_mon = 11; /* Month */
t.tm_year = 56; /* Year - does not include century */
t.tm_wday = 4; /* Day of the week */
t.tm_yday = 0; /* Does not show in asctime */
t.tm_isdst = 0; /* Is Daylight SavTime; does not show in asctime */
/* converts structure to null terminated
string */
strcpy(str, asctime(t));
printf("%s\n", str);
return 0;
}
函数名: asin
功 能: 反正弦函数
用 法: double asin(double x);
程序例:
#include stdio.h
#include math.h
int main(void)
{
double result;
double x = 0.5;
result = asin(x);
printf("The arc sin of %lf is %lf\n", x, result);
return(0);
}
函数名: assert
功 能: 测试一个条件并可能使程序终止
用 法: void assert(int test);
程序例:
#include assert.h
#include stdio.h
#include stdlib.h
struct ITEM {
int key;
int value;
};
/* add item to list, make sure list is not null */
void additem(struct ITEM *itemptr) {
assert(itemptr != NULL);
/* add item to list */
}
int main(void)
{
additem(NULL);
return 0;
}
函数名: atan
功 能: 反正切函数
用 法: double atan(double x);
程序例:
#include stdio.h
#include math.h
int main(void)
{
double result;
double x = 0.5;
result = atan(x);
printf("The arc tangent of %lf is %lf\n", x, result);
return(0);
}
函数名: atan2
功 能: 计算Y/X的反正切值
用 法: double atan2(double y, double x);
程序例:
#include stdio.h
#include math.h
int main(void)
{
double result;
double x = 90.0, y = 45.0;
result = atan2(y, x);
printf("The arc tangent ratio of %lf is %lf\n", (y / x), result);
return 0;
}
函数名: atexit
功 能: 注册终止函数
用 法: int atexit(atexit_t func);
程序例:
#include stdio.h
#include stdlib.h
void exit_fn1(void)
{
printf("Exit function #1 called\n");
}
void exit_fn2(void)
{
printf("Exit function #2 called\n");
}
int main(void)
{
/* post exit function #1 */
atexit(exit_fn1);
/* post exit function #2 */
atexit(exit_fn2);
return 0;
}
函数名: atof
功 能: 把字符串转换成浮点数
用 法: double atof(const char *nptr);
程序例:
#include stdlib.h
#include stdio.h
int main(void)
{
float f;
char *str = "12345.67";
f = atof(str);
printf("string = %s float = %f\n", str, f);
return 0;
}
函数名: atoi
功 能: 把字符串转换成长整型数
用 法: int atoi(const char *nptr);
程序例:
#include stdlib.h
#include stdio.h
int main(void)
{
int n;
char *str = "12345.67";
n = atoi(str);
printf("string = %s integer = %d\n", str, n);
return 0;
}
函数名: atol
功 能: 把字符串转换成长整型数
用 法: long atol(const char *nptr);
程序例:
#include stdlib.h
#include stdio.h
int main(void)
{
long l;
char *str = "98765432";
l = atol(lstr);
printf("string = %s integer = %ld\n", str, l);
return(0);
}
c语言冒泡排序问题具体程序如下，有问题的部分是down和up函数。运行了你就知道问题所在#include
j循环倒了，i从0到n，j就要从n到i，stu[j]stu[j-1]交换他们，这样才是正确的
up()
{int i,j;
clrscr();
for(i=0;in-1;i++)
for(j=n-1;ji;j++)
if(stu[j].scorestu[j-1].score)
{k=stu[j];stu[j]=stu[j-1];stu[j-1]=stu[j];}
for(i=0;in;i++) printf(" %s %d\n",stu[i].num,stu[i].score);}
如何读懂C语言库函数
用法看文档
至于内容， 那个很多根本没内容， 当然没法“读懂”。
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