分析SQL中parametertablemanagement问题-创新互联
这篇文章主要讲解了“分析SQL中parameter table management问题”,文中的讲解内容简单清晰,易于学习与理解,下面请大家跟着小编的思路慢慢深入,一起来研究和学习“分析SQL中parameter table management问题”吧!
创新互联长期为1000多家客户提供的网站建设服务,团队从业经验10年,关注不同地域、不同群体,并针对不同对象提供差异化的产品和服务;打造开放共赢平台,与合作伙伴共同营造健康的互联网生态环境。为两当企业提供专业的网站设计制作、网站设计,两当网站改版等技术服务。拥有10多年丰富建站经验和众多成功案例,为您定制开发。1.查询要执行的SQL,是否有子游标,没有子游标
SYS@honor > select sql_id,child_number,sql_text from v$sql where sql_text like '%SELECT count(*) FROM t%'; SQL_ID CHILD_NUMBER SQL_TEXT ------------- ------------ -------------------------------------------------------------------------------- gxfdy6zpjvmtc 0 select sql_id,child_number,sql_text from v$sql where sql_text like '%SELECT coun
2.查询当前会话sid,session1执行相关存储过程
session1 > select * from v$mystat where statistic#=0; SID STATISTIC# VALUE ---------------------------------------- ---------------------------------------- ---------------------------------------- 49 0 0 session1 > DECLARE 2 a number; 3 v varchar2(20):='haha'; 4 BEGIN 5 FOR c IN 1..100000 6 LOOP 7 EXECUTE IMMEDIATE 'ALTER SESSION SET optimizer_index_cost_adj = 1'; EXECUTE IMMEDIATE 'SELECT count(*) FROM t' into a; 9 END LOOP; 10 END; 11 / PL/SQL procedure successfully completed.
2.查询当前会话sid,session2执行相关存储过程
session2 > select * from v$mystat where statistic#=0; SID STATISTIC# VALUE ---------------------------------------- ---------------------------------------- ---------- 58 0 ########## session2 > DECLARE 2 a number; 3 v varchar2(20):='haha'; 4 BEGIN 5 FOR c IN 1..100000 6 LOOP 7 EXECUTE IMMEDIATE 'ALTER SESSION SET optimizer_index_cost_adj = 2'; EXECUTE IMMEDIATE 'SELECT count(*) FROM t' into a; 9 END LOOP; 10 END; 11 / PL/SQL procedure successfully completed.
3.查询查询SQL子游标,发现有两个子游标
SYS@honor > select sql_id,child_number,sql_text from v$sql where sql_text like '%SELECT count(*) FROM t%'; SQL_ID CHILD_NUMBER SQL_TEXT ------------- ------------ -------------------------------------------------------------------------------- 5nbjnx26pn4rh 0 DECLARE a number; BEGIN FOR c IN 1..100000 LOOP EXECUTE IMMEDIAT 5tjqf7sx5dzmj 0 SELECT count(*) FROM t 5tjqf7sx5dzmj 1 SELECT count(*) FROM t f14srtthcadyq 0 DECLARE a number; v varchar2(20):='haha'; BEGIN FOR c IN 1..100000 L gxfdy6zpjvmtc 0 select sql_id,child_number,sql_text from v$sql where sql_text like '%SELECT coun
4.查询会话执行期间,等待事件,根据原理,两个存储过程执行过程中,会引发select语句子游标持有父游标的指向子游标的handle导致的cursor pin S wait on x争用,但是意外发现发生了latch free,经过查询latch类型,为parameter table management,并没有见过相关latch,去查Mos,发现命中bug,在12.2中修复,或者打补丁
SYS@honor1 > select sid,USERNAME,EVENT,sql_id,SQL_CHILD_NUMBER,p1,p2,p3,WAIT_CLASS,WAIT_TIME,BLOCKING_SESSION,BLOCKING_SESSION_STATUS from v$session where sid in ('49','58'); SID USERNAME EVENT SQL_ID SQL_CHILD_NUMBER P1 P2 P3 WAIT_CLASS WAIT_TIME BLOCKING_SESSION BLOCKING_SESSION_STATUS ---------- ----------- ------------------- ------------- ---------------- ---------- ---------- ---------- ----------- ---------- ---------------- ----------------------- 49 LIBAI latch free 5nbjnx26pn4rh 0 1610665040 24 0 Other -1 NOT IN WAIT 58 LIBAI latch free 5tjqf7sx5dzmj 1 1610665040 24 0 Other -1 NOT IN WAIT SYS@honor1 > select to_char('1610665040','xxxxxxxxxxxx') from dual; TO_CHAR('1610 ------------- 6000cc50 SYS@honor1 > select addr,latch#,hash,name from v$latch where addr like '%6000CC50%'; ADDR LATCH# HASH NAME ---------------- ---------------------------------------- ---------------------------------------- ---------------------------------------- 000000006000CC50 24 722869772 parameter table management
5.bug说明:
Session Waiting on 'Parameter Table Management' Latch (Doc ID 2271591.1) |
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感谢各位的阅读,以上就是“分析SQL中parameter table management问题”的内容了,经过本文的学习后,相信大家对分析SQL中parameter table management问题这一问题有了更深刻的体会,具体使用情况还需要大家实践验证。这里是创新互联,小编将为大家推送更多相关知识点的文章,欢迎关注!
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