LeetCode知识点总结-538-创新互联
LeetCode 538. Convert BST to Greater Tree
题目
文章题目:LeetCode知识点总结-538-创新互联
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考点 | 难度 |
---|---|
DFS | Medium |
Given the root of a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus the sum of all keys greater than the original key in BST.
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The left subtree of a node contains only nodes with keys less than the node’s key.
The right subtree of a node contains only nodes with keys greater than the node’s key.
Both the left and right subtrees must also be binary search trees.
inverse traversal
答案class Solution(object):
def convertBST(self, root):
self.val = 0
def visit(root):
if root:
visit(root.right)
root.val += self.val
self.val = root.val
visit(root.left)
visit(root)
return root
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文章题目:LeetCode知识点总结-538-创新互联
本文网址:http://ybzwz.com/article/csicpi.html